Question

In the following structure, the percentage of the 's' character in the lone pair occupy by the oxygen atom is ______.

Given: Cos θ = −0.99

Options

• 0.26

• 1.89

• 2.64

• 3.12

Answer 1

In the following structure, the percentage of the 's' character in the lone pair occupy by the oxygen atom is 0.26.

Explanation:

Cos θ = `"s"/("s" - 1)` = −0.99

s = `0.99/1.99 xx 100` = = 49.74%

% of the 's' character in lone pair by oxygen = 2%

s = 100 – (2 × 49.74)

⇒ % of the s = 0.26