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Question
In the given figure, A, B and C are three points on a circle with centre O such that ∠BOC = 30° and ∠AOB = 60°. If D is a point on the circle other than the arc ABC, find ∠ADC.
Solution
It can be observed that
∠AOC = ∠AOB + ∠BOC
= 60° + 30°
= 90°
We know that the angle subtended by an arc at the centre is double the angle subtended by any point on the remaining part of the circle.
∠ADC = `1/2angleAOC`
= `1/2 xx 90^@`
= 45°
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