Advertisements
Advertisements
Question
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠ AED = 60° and ∠ ACD = 45°. Calculate: AE.
Solution
From the right triangle ADE we have
sin 60° = `"AD"/"AE"`
`sqrt(3)/(2) = (2)/"AE"`
AE = `(4)/sqrt(3)`.
APPEARS IN
RELATED QUESTIONS
Find 'x', if :
Find 'x', if :
Find 'x', if:
Find angle 'A' if:
In the given figure, ∠B = 60°, AB = 16 cm and BC = 23 cm,
Calculate:
- BE
- AC
In right-angled triangle ABC; ∠ B = 90°. Find the magnitude of angle A, if: AB is √3 times of BC.
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 15 m of the tower; find length of the ladder.
A kite is attached to a 100 m long string. Find the greatest height reached by the kite when its string makes an angles of 60° with the level ground.
Find PQ, if AB = 150 m, ∠P = 30° and ∠Q = 45°.
.
If tan x° = `(5)/(12)`,
tan y° = `(3)/(4)` and AB = 48 m; find the length of CD.
