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Question
In the given figure. Find RP and PS using the information given in ∆PSR.
Solution
In ∆PSR,
∠S = 90∘, ∠P = 30∘, ∴ ∠R = 60∘
By 30∘ − 60∘ − 90∘ theorem,
RS = `1/2` RP
6 = `1/2` RP
6 × 2 = RP
RP = 12 ...(1)
PS = `sqrt3/2` RP
= `sqrt3/2xx12`
= `6sqrt3` ...(2)
Hence, RP = 12 units and PS = `6sqrt3`
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