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In the widest part of the horizontal pipe, oil is flowing at a rate of 2 m/sec. The speed (in m/s) of the flow of oil in the narrow part of the tube if the pressure difference -

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Question

In the widest part of the horizontal pipe, oil is flowing at a rate of 2 m/sec. The speed (in m/s) of the flow of oil in the narrow part of the tube if the pressure difference in the broad and narrow parts of the pipe is 0.25 ρoilg, is ______ m/s.

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  • 1.00

  • 2.00

  • 3.00

  • 4.00

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Solution

In the widest part of the horizontal pipe, oil is flowing at a rate of 2 m/sec. The speed (in m/s) of the flow of oil in the narrow part of the tube if the pressure difference in the broad and narrow parts of the pipe is 0.25 ρoilg, is 3.00 m/s.

Explanation:

`(Deltarho)/(rhog) = (u^2 - 4)/(2g)`

`250 xx 10^-3 xx 10 = (u^2 - 4)/2`

⇒ u2 - 4 = 5

u2 = 9

u = 3 m/s

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