English

Indicate the number of unpaired electrons in Si (Z = 14). - Chemistry

Advertisements
Advertisements

Question

Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).

Short Answer

Solution

Electronic configuration of \[\ce{Si}\] (Z = 14) is 1s2 2s2 2p6 3s2 3p2

Orbital diagram:

↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓  
1s 2s 2p 3s 3p

Number of unpaired electrons = 2

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Structure of Atom - Exercises [Page 54]

APPEARS IN

Balbharati Chemistry [English] 11 Standard
Chapter 4 Structure of Atom
Exercises | Q 6. (S)(a) | Page 54

RELATED QUESTIONS

Using s, p, d notations, describe the orbital with the following quantum numbers n = 1, l = 0.


Using s, p, d notations, describe the orbital with the following quantum numbers n = 4; l = 2.


Choose the correct option.

p-orbitals are _________ in shape.


State Hund’s rule of maximum multiplicity with a suitable example.


Explain the anomalous behaviour of copper.


Write condensed orbital notation of electronic configuration of the following element:

Carbon (Z = 6)


Write condensed orbital notation of electronic configuration of the following element:

Oxygen (Z = 8)


Explain in brief, the significance of the azimuthal quantum number.


Indicate the number of unpaired electron in:

Cr (Z = 24)


Which one of the following orders is CORRECT in case of energy of the given subshells?

P: n = 4; l = 3

Q: n = 5; I = 1

R: n = 5; l = 0

S: n = 4; l = 2


How many electrons in 19K have n = 3, l = 1?


The three electrons have the following set of quantum numbers:

X = 6, 1, −1, `+1/2`

Y = 6, 0, 0, `+1/2`

Z = 5, 1, 0, `+1/2`

Identify the CORRECT statement.


How many electrons can fit in the orbital for which n = 4 and l = 2?


Which of the following has a greater number of electrons than neutrons?

(Mass number of Mg, C, O and Na is 24, 12, 16 and 23 respectively).


Which one of the following is NOT possible?


Number of angular nodes for 4d orbital is ______.


The pair of ions having same electronic configuration is ______.


Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals:

(i)  (a) `n = 3, l = 2, m_l = -2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = -1, m_s = - 1/2`
   
(ii)  (a) `n = 3, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iii) (a) `n = 4, l = 1, m_l = 1, m_s = + 1/2`
  (b) `n = 3, l = 2, m_l = 1, m_s = + 1/2`
   
(iv)  (a) `n = 3, l = 2, m_l = +2, m_s = - 1/2`
  (b) `n = 3, l = 2, m_l = +2, m_s = + 1/2`

Which of the following sets of quantum numbers are correct?

  `n` `l` `m_l`
(i) 1 1 +2
(ii) 2 1 +1
(iii) 3 2 –2
(iv) 3 4 –2

Which of the following statements concerning the quantum numbers are correct?

(i) Angular quantum number determines the three dimensional shape of the orbital.

(ii) The principal quantum number determines the orientation and energy of the orbital.

(iii) Magnetic quantum number determines the size of the orbital.

(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.


Which of the following orbitals are degenerate?

3dxy, 4dxy 3dz2, 3dyz, 4dyz, 4dz2  


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

1s, 2s, 3s, 2p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, arrange the following orbitals in the increasing order of energy.

4s, 3s, 3p, 4d


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

4d, 4f, 5s, 5p


The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.

Based upon the above information, solve the questions given below:

Which of the following orbitals has the lowest energy?

5p, 5d, 5f, 6s, 6p


The electronic configuration of valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?


Match the following

(i) Photon (a) Value is 4 for N shell
(ii) Electron (b) Probability density
(iii) ψ2 (c) Always positive value
(iv) Principal quantum number n (d) Exhibits both momentum and wavelength

In the case of R, S configuration the group having the highest priority is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×