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Question
Integrate the following functions with respect to x:
`1/(6 - 4x)`
Solution
`int ("d"x)/("a"x + "b") = 1/"a" log |"a"x + "b"| + "c"`
`int ("d"x)/(6 - 4x) = 1/(-4) log|6 - 4x| + "c"`
= `-1/4 log|6 - 4x| + "c"`
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Choose the correct alternative:
If `int f"'"(x)"e"^(x^2) "d"x = (x - 1)"e"^(x^2) + "c"`, then`f(x)` is
