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प्रश्न
Integrate the following functions with respect to x:
`1/(6 - 4x)`
उत्तर
`int ("d"x)/("a"x + "b") = 1/"a" log |"a"x + "b"| + "c"`
`int ("d"x)/(6 - 4x) = 1/(-4) log|6 - 4x| + "c"`
= `-1/4 log|6 - 4x| + "c"`
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