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प्रश्न
Integrate the following functions with respect to x:
`1/sqrt(1 + 36x^2)`
उत्तर
`int ("d"x)/(1 + ("a"x + "b")^2) = 1/"a" tan^-1 ("a"x + "b") + "c"`
`int ("d"x)/(1 + 36x^2) = int ("d"x)/(1 + (6x)^2`
= `1/6 tan^-1 (6x) + "c"`
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