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Question
Integrate the following with respect to x.
`(log x)^3/x`
Solution
Let log x = z
Then `1/x "d"x = "d"z`
So `int (log x)^3/x "d"x = int z^3"d"z`
= `z^4/4 + "c"`
= `(log x)^4/4 + "c"`
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