Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x.
`(log x)^3/x`
उत्तर
Let log x = z
Then `1/x "d"x = "d"z`
So `int (log x)^3/x "d"x = int z^3"d"z`
= `z^4/4 + "c"`
= `(log x)^4/4 + "c"`
APPEARS IN
संबंधित प्रश्न
Integrate the following with respect to x.
x3e3x
Integrate the following with respect to x.
`x^5 "e"^x`
Integrate the following with respect to x.
`(4x + 2) sqrt(x^2 + x + 1)`
Integrate the following with respect to x
`1/(x log x)`
Integrate the following with respect to x.
`x/(2x^4 - 3x^2 - 2)`
Integrate the following with respect to x.
`"e"^x [(x - 1)/(x + 1)^3]`
Integrate the following with respect to x.
`1/(2x^2 + 6x - 8)`
Integrate the following with respect to x.
`x^3/sqrt(x^8 - 1)`
Choose the correct alternative:
`int (sin5x - sinx)/(cos3x) "d"x` is
Evaluate the following integral:
`int 1/(sqrt(x + 2) - sqrt(x + 3)) "d"x`
