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Question
Inverse of the statement pattern (p ∨ q) → (p ∧ q) is
(A) (p ∧ q) → (p ∨ q)
(B) ∼ (p ∨ q) → (p ∧ q)
(C) (∼ p ∨ ∼ q) → (∼ p ∧ ∼ q)
(D) (∼ p ∧ ∼ q) → (∼ p ∨ ∼ q)
Solution
(D) (∼ p ∧ ∼ q) → (∼ p ∨ ∼ q)
statement pattern: (p ∨ q ) → ( p ∧ q)
Its inverse is
~ (p ∨ q ) → ~ ( p ∧ q)
≡ (∼ p ∧ ∼ q) → (∼ p ∨ ∼ q)
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