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Question
Is the following sequences are A.P.? If is A.P. find the common difference.
0, –4, –8, –12,...
Solution
0, –4, –8, –12,...
Here, t1 = 0, t2 = -4, t3 = -8, t4 = -12
∴ t2 - t1 = -4 - 0 = -4
∴ t3 - t2 = -8 - (-4) = -8 + 4 = -4
∴ t4 - t3 = -12 - (-8) = -12 + 8 = -4
The difference between two consecutive terms is constant.
Hence, the given sequence is an A.P. and the common difference (d) is -4.
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