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Chapters
2: Quadratic Equations
▶ 3: Arithmetic Progression
4: Financial Planning
5: Probability
6: Statistics
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Solutions for Chapter 3: Arithmetic Progression
Below listed, you can find solutions for Chapter 3 of Maharashtra State Board Balbharati for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board.
Balbharati solutions for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board 3 Arithmetic Progression Practice Set 3.1 [Pages 61 - 62]
Which of the following sequences are A.P.? If they are A.P. find the common difference.
2, 4, 6, 8, ...
Which of the following sequences are A.P.? If they are A.P. find the common difference.
Which of the following sequences are A.P.? If they are A.P. find the common difference.
–10, –6, –2, 2,...
Is the following sequences are A.P.? If is A.P. find the common difference.
0.3, 0.33, 0.333,...
Is the following sequences are A.P.? If is A.P. find the common difference.
0, –4, –8, –12,...
Is the following sequences are A.P.? If is A.P. find the common difference.
Which of the following sequences are A.P.? If they are A.P. find the common difference.
`3, 3 + sqrt2, 3 + 2sqrt2, 3 + 3sqrt2, ...`
Which of the following sequences are A.P. ? If they are A.P. find the common difference .
127, 132, 137,...
Write an A.P. whose first term is a and the common difference is d in the following.
a = 10, d = 5
Write an A.P. whose first term is a and common difference is d in the following.
a = –3, d = 0
Write an A.P. whose first term is a and common difference is d in the following.
Write an A.P. whose first term is a and common difference is d in the following.
a = –1.25, d = 3
Write an A.P. whose first term is a and common difference is d in the following.
a = 6, d = –3
Write an A.P. whose first term is a and common difference is d in the following.
a = –19, d = –4
Find the first term and common difference for the A.P.
5, 1, –3, –7,...
Find the first term and common difference for the A.P.
0.6, 0.9, 1.2,1.5,...
Find the first term and common difference for the A.P.
127, 135, 143, 151,...
Find the first term and common difference for the A.P.
`1/4,3/4,5/4,7/4,...`
Balbharati solutions for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board 3 Arithmetic Progression Practice Set 3.2 [Page 66]
Write the correct number in the given boxes from the following A. P.
1, 8, 15, 22,...
Here a =Here a = t1 =
, t2 =
, t3 =
,
t2 – t1 = –
=
t3 – t2 = –
=
∴ d =
Write the correct number in the given boxes from the following A. P.
3, 6, 9, 12,...
Here t1 = t2 =
, t3 =
, t4 =
,
t2 – t1 = , t3 – t2 =
∴ d =
Write the correct number in the given boxes from the following A. P.
–3, –8, –13, –18,...
Here t3 = , t2 =
, t4 =
, t1 =
,
t2 – t1 = , t3 – t2 =
∴ a =
, d =
Write the correct number in the given boxes from the following A. P.
70, 60, 50, 40,...
Here t1 = , t2 =
, t3 =
,...
∴ a = , d =
Decide whether the following sequence is an A.P., if so find the 20th term of the progression:
–12, –5, 2, 9, 16, 23, 30, ..............
Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.
Find the 19th term of the following A.P.:
7, 13, 19, 25, ...
Find the 27th term of the following A.P.
9, 4, –1, –6, –11,...
Find how many three digit natural numbers are divisible by 5.
The 11th term and the 21st term of an A.P. are 16 and 29 respectively, then find the 41th term of that A.P.
In the natural numbers from 10 to 250, how many are divisible by 4?
In an A.P. 17th term is 7 more than its 10th term. Find the common difference.
Balbharati solutions for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board 3 Arithmetic Progression Practice Set 3.3 [Pages 72 - 73]
First term and the common differences of an A.P. are 6 and 3 respectively; find S27.
Solution: First term = a = 6, common difference = d = 3, S27 = ?
Sn = `"n"/2 [square + ("n" - 1)"d"]` - Formula
Sn = `27/2 [12 + (27 - 1)square]`
= `27/2 xx square`
= 27 × 45
S27 = `square`
Find the sum of first 123 even natural numbers.
In an A.P. 19th term is 52 and 38th term is 128, find sum of first 56 terms.
Complete the following activity to find the sum of natural numbers from 1 to 140 which are divisible by 4.
Sum of numbers from 1 to 140, which are divisible by 4 = `square`
Sum of first 55 terms in an A.P. is 3300, find its 28th term.
In an A.P. sum of three consecutive terms is 27 and their product is 504, find the terms.
(Assume that three consecutive terms in A.P. are a – d, a, a + d).
Find four consecutive terms in an A.P. whose sum is 12 and sum of 3rd and 4th term is 14.
(Assume the four consecutive terms in A.P. are a – d, a, a + d, a +2d)
If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term?
Balbharati solutions for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board 3 Arithmetic Progression Practice Set 3.4 [Page 78]
On 1st Jan 2016, Sanika decides to save Rs 10, Rs 11 on second day, Rs 12 on third day. If she decides to save like this, then on 31st Dec 2016 what would be her total saving?
A man borrows Rs 8000 and agrees to repay with a total interest of Rs 1360 in 12 monthly installments. Each installment being less than the preceding one by Rs 40. Find the amount of the first and last installments.
Sachin invested in a national saving certificate scheme. In the first year he invested Rs 5000 , in the second year Rs 7000, in the third year Rs 9000 and so on. Find the total amount that he invested in 12 years.
There is an auditorium with 27 rows of seats. There are 20 seats in the first row, 22 seats in the second row, 24 seats in the third row and so on. Find the number of seats in the 15th row and also find how many total seats are there in the auditorium?
Kargil’s temperature was recorded in a week from Monday to Saturday. All readings were in A.P. The sum of temperatures of Monday and Saturday was 5°C more than sum of temperatures of Tuesday and Saturday. If temperature of Wednesday was –30° celsius then find the temperature on the other five days.
On the world environment day tree plantation programme was arranged on a land which is triangular in shape. Trees are planted such that in the first row there is one tree, in the second row there are two trees, in the third row three trees and so on. Find the total number of trees in the 25 rows.
Balbharati solutions for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board 3 Arithmetic Progression Problem Set 3 [Pages 78 - 80]
Choose the correct alternative answer for the following question .
The sequence –10, –6, –2, 2,...
is an A.P.,Reason d = -16
is an A.P Reason d = 4
is an A.P.,Reason d = -4
is not an A.P.
Choose the correct alternative answer for the following question .
First four terms of an A.P. are ....., whose first term is –2 and common difference is –2.
-2,0,2,4
-2,4 ,-8,16
-2, -4,-6,-8
-2, -4 ,-8,-16
Choose the correct alternative answer for the following question .
What is the sum of the first 30 natural numbers ?
464
465
462
461
For an given A.P., t7 = 4, d = −4, then a = ______.
6
7
20
28
Choose the correct alternative answer for the following question.
For an given A.P. a = 3.5, d = 0, n = 101, then tn = ....
0
3.5
103.5
104.5
Choose the correct alternative answer for the following question .
In an A.P. first two terms are –3, 4 then 21st term is ...
-143
143
137
17
Choose the correct alternative answer for the following question .
If for any A.P. d = 5 then t18 – t13 = ....
5
20
25
30
The Sum of first five multiples of 3 is ______.
45
55
15
75
Choose the correct alternative answer for the following question .
15, 10, 5,... In this A.P sum of first 10 terms is...
-75
-125
75
125
Choose the correct alternative answer for the following question .
In an A.P. 1st term is 1 and the last term is 20. The sum of all terms is = 399 then n = ....
42
38
21
19
Find the fourth term from the end in an A.P. –11, –8, –5,...., 49.
In an A.P. the 10th term is 46 sum of the 5th and 7th term is 52. Find the A.P.
The A.P. in which 4th term is –15 and 9th term is –30. Find the sum of the first 10 numbers.
Two A.P.’ s are given 9, 7, 5, . . . and 24, 21, 18, . . . . If nth term of both the progressions are equal then find the value of n and nth term.
If sum of 3rd and 8th terms of an A.P. is 7 and sum of 7th and 14th terms is –3 then find the 10th term.
In an A.P. the first term is – 5 and the last term is 45. If the sum of all numbers in the A.P. is 120, then how many terms are there? What is the common difference?
Sum of 1 to n natural numbers is 36, then find the value of n.
Divide 207 in three parts, such that all parts are in A.P. and product of two smaller parts will be 4623.
There are 37 terms in an A.P., the sum of three terms placed exactly at the middle is 225 and the sum of last three terms is 429. Write the A.P.
If first term of an A.P. is a, second term is b and last term is c, then show that sum of all terms is \[\frac{\left( a + c \right) \left( b + c - 2a \right)}{2\left( b - a \right)}\].
If the sum of first p terms of an A.P. is equal to the sum of first q terms then show that the sum of its first (p + q) terms is zero. (p ≠ q)
If m times the mth term of an A.P. is eqaul to n times nth term then show that the (m + n)th term of the A.P. is zero.
Rs 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. For this complete the following activity.
Solutions for 3: Arithmetic Progression
Balbharati solutions for Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board chapter 3 - Arithmetic Progression
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Concepts covered in Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board chapter 3 Arithmetic Progression are Introduction to Sequence, Arithmetic Progressions Examples and Solutions, Terms in a sequence, Arithmetic Progression, General Term of an Arithmetic Progression, Sum of First ‘n’ Terms of an Arithmetic Progressions, Geometric Progression, General Term of an Geomatric Progression, Sum of the First 'N' Terms of an Geometric Progression, Geometric Mean, Arithmetic Mean - Raw Data, Concept of Ratio.
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