Advertisements
Advertisements
Question
Write an A.P. whose first term is a and common difference is d in the following.
a = 6, d = –3
Solution
a = 6, d = –3
t1 = a = 6 ...[Given]
t2 = t1 + d = 6 + (-3) = 6 - 3 = 3
t3 = t2 + d = 3 + (-3) = 3 - 3 = 0
t4 = t3 + d = 0 + (-3) = 0 - 3 = -3
∴ The required A.P. is 6, 3, 0, -3, ...
APPEARS IN
RELATED QUESTIONS
If Sn denotes the sum of first n terms of an A.P., prove that S30 = 3[S20 − S10]
In an AP, given a = 7, a13 = 35, find d and S13.
Find the sum of the following arithmetic progressions:
`(x - y)/(x + y),(3x - 2y)/(x + y), (5x - 3y)/(x + y)`, .....to n terms
Find the common difference of an AP whose first term is 5 and the sum of its first four terms is half the sum of the next four terms.
Find four numbers in AP whose sum is 8 and the sum of whose squares is 216.
The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.
If the ratio of sum of the first m and n terms of an AP is m2 : n2, show that the ratio of its mth and nth terms is (2m − 1) : (2n − 1) ?
Find the 25th term of the AP \[- 5, \frac{- 5}{2}, 0, \frac{5}{2}, . . .\]
Choose the correct alternative answer for the following question .
The sequence –10, –6, –2, 2,...
Fill up the boxes and find out the number of terms in the A.P.
1,3,5,....,149 .
Here a = 1 , d =b`[ ], t_n = 149`
tn = a + (n-1) d
∴ 149 =`[ ] ∴149 = 2n - [ ]`
∴ n =`[ ]`
The sum of 5th and 9th terms of an A.P. is 30. If its 25th term is three times its 8th term, find the A.P.
Write the sum of first n odd natural numbers.
If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =
In a Arithmetic Progression (A.P.) the fourth and sixth terms are 8 and 14 respectively. Find that:
(i) first term
(ii) common difference
(iii) sum of the first 20 terms.
Obtain the sum of the first 56 terms of an A.P. whose 18th and 39th terms are 52 and 148 respectively.
Find S10 if a = 6 and d = 3
First four terms of the sequence an = 2n + 3 are ______.
In an AP if a = 1, an = 20 and Sn = 399, then n is ______.
Find the sum:
`(a - b)/(a + b) + (3a - 2b)/(a + b) + (5a - 3b)/(a + b) +` ... to 11 terms
If Sn denotes the sum of first n terms of an AP, prove that S12 = 3(S8 – S4)
