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Question
It is given that m a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?
Solution
Let E ⟶ event of 2 students having same birthday P(E) is given as 0.992
Let (`barE` ) ⟶ event of 2 students not having same birthday.
We know that, P(E) + P(`barE` ) = 1
P(`barE`) = 1 − 𝑃(𝐸)
= 1 – 0.992
= 0.008
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