Justify that the following reaction is redox reaction: \[\ce{4BCl3(g) + 3LiAlH4(s) → 2B2H6(g) + 3LiCl(s) + 3 AlCl3(s)}\]

The oxidation number of each element in the given reaction can be represented as: +3 -1 +1 +3 -1 -3 +1 +1 -1 +3 -1\[\ce{4BCl3(g) + 3LiAlH4(s) → 2B2H6(g) + 3LiCl(s) + 3 AlCl3(s)}\] In this reaction, the oxidation number of B decreases from +3 in BCl3 to –3 in B2H6. i.e., BCl3 is reduced to B2H6. Also, the oxidation number of H increases from –1 in LiAlH4 to +1 in B2H6 i.e., LiAlH4 is oxidized to B2H6. Hence, the given reaction is a redox reaction.

Justify that the Following Reactions Are Redox Reactions: 4bcl3(G) + 3lialh4(S) → 2b2h6(G) + 3licl(S) + 3 Alcl3 (S) - Chemistry

Question

Justify that the following reaction is redox reaction:

$4 BCl_{3} (g) + 3 LiAlH_{4} (s) ⟶ 2 B_{2} H_{6} (g) + 3 LiCl (s) + 3 AlCl_{3} (s)$

Numerical

Solution

The oxidation number of each element in the given reaction can be represented as:

+3 -1 +1 +3 -1 -3 +1 +1 -1 +3 -1
$4 BCl_{3} (g) + 3 LiAlH_{4} (s) ⟶ 2 B_{2} H_{6} (g) + 3 LiCl (s) + 3 AlCl_{3} (s)$

In this reaction, the oxidation number of B decreases from +3 in BCl₃ to –3 in B₂H₆. i.e., BCl₃ is reduced to B₂H₆. Also, the oxidation number of H increases from –1 in LiAlH₄ to +1 in B₂H₆ i.e., LiAlH₄ is oxidized to B₂H₆. Hence, the given reaction is a redox reaction.

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Oxidation Number - Types of Redox Reactions

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Q 8.3 - (c)Q 8.3 - (b)Q 8.3 - (d)

Chapter 8: Redox Reactions - EXERCISES [Page 280]

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Chapter 8 Redox Reactions
EXERCISES | Q 8.3 - (c) | Page 280

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