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Let a→,b→,c→ be three vectors of magnitudes 3, 4 and 5 respectively. If each one is petpendicular to the sum of the other two vectors, then |a→+b→+c→| = -

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Question

Let a,b,c be three vectors of magnitudes 3, 4 and 5 respectively. If each one is petpendicular to the sum of the other two vectors, then |a+b+c| =

Options

  • 5

  • 32

  • 52

  • 12

MCQ

Solution

52

Explanation:

We have |a| = 3, |b| = 4 and |c| = 5.

It is given that a(b+c),b(c+a) and c(a+b)

a.(b+c) = 0, b.(c+a) = 0, c.(a+b) = 0

a.b+a .c = 0, b.c+b.a = 0, c.a+c.b = 0

Adding all these, we get, 2(a.b+b.c+c.a) = 0

a.b+b.c+c.a = 0

Now, |a+b+c|2=|a|2+|b|2+|c|2+2(a.b+b.c+c.a) = 32 + 42 + 52 + 0 = 50

|a+b+c|=50=52.

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