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Question
Let l be the lower class limit of a class-interval in a frequency distribution and m be the mid point of the class. Then, the upper class limit of the class is
Options
- m+ \[\frac{l + m}{2}\]
l+ \[\frac{m + l}{2}\]
2m − 1
m − 2l
Solution
Given that, the lower class limit of a class-interval is l and the mid-point of the class is m. Let u be the upper class limit of the class-interval. Therefore, we have
`m = (l+u) /2`
⇒ l +u = 2m
⇒ u = 2m - 1
Thus the upper class limit of the class is (2m - l) .
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