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Question
Let S be the relation defined by S = {(l1, l2) : l1 is perpendicular to l2} check whether the relation S is symmetric and transitive.
Case Study
Solution
Given relation, S = {(l1, l2) : l1 is perpendicular to l2}
Symmetric l1 ⊥ l2 ⇒ l2 || l1
(Two lines are perpendicular to each other)
Hence, S is symmetric.
Transitive:
Let l1 ⊥ l2 and l2 ⊥ l3 ⇒ l1 || l3
Thus, relation S is not transitive.
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