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Question
Make h the subject of the formula K = `sqrt("hg"/"d"^2 - "a"^2`. Find h, when k = -2, a = -3, d = 8 and g = 32.
Solution
K = `sqrt("hg"/"d"^2 - "a"^2`
Squaring both sides, we get
⇒ K2 = `"hg"/"d"^2 -"a"^2`
⇒ K2 + a2 = `"hg"/"d"^2`
⇒ (K2 + a2)d2 = hg
⇒ h = `(("K"^2 + "a"^2)"d"^2)/"g"`
Substituting k = 2, a = -3, d = 8 and g = 32, we get
h = `(((-2)^2 + (-3)^2) (8)^2)/(32)`
= `((4 + 9)64)/(32)`
= 26.
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