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Question
Make h the subject of the formula R = `"h"/(2)("a" - "b")`. Find h when R = 108, a = 16 and b = 12.
Solution
R = `"h"/(2)("a" - "b")`
⇒ 2R = h(a - b)
⇒ h = `(2"R")/("a" - "b")`
Substituting R = 108, a = 16 and b = 12, we get
h = `(2 xx 108)/(16 - 12)`
= `(2 xx 108)/(4)`
= 54.
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