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Question
Making use of the cube root table, find the cube root
9800 .
Solution
We have: \[9800 = 98 \times 100\]
∴ \[\sqrt[3]{9800} = \sqrt[3]{98 \times 100} = \sqrt[3]{98} \times \sqrt[3]{100}\]
By cube root table, we have:
\[\sqrt[3]{98} = 4 . 610 \text{ and } \sqrt[3]{100} = 4 . 642\]
∴ \[\sqrt[3]{9800} = \sqrt[3]{98} \times \sqrt[3]{100} = 4 . 610 \times 4 . 642 = 21 . 40\] (upto three decimal places)
Thus, the required cube root is 21.40.
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