Question

Making use of the cube root table, find the cube root
9800 .

Answer 1

We have: $$9800=98\times 100$$

∴ $$\sqrt[3]{9800}=\sqrt[3]{98\times 100}=\sqrt[3]{98}\times \sqrt[3]{100}$$

By cube root table, we have: 

$$\sqrt[3]{98}=4.610\text{ and }\sqrt[3]{100}=4.642$$

∴ $$\sqrt[3]{9800}=\sqrt[3]{98}\times \sqrt[3]{100}=4.610\times 4.642=21.40$$ (upto three decimal places)

Thus, the required cube root is 21.40.