English

Making Use Only of Substances Chosen from Those Given Below: Dilute Sulphuric Acid Sodium Carbonate Zinc Sodium Sulphite Lead Salcium Carbonate - Chemistry

Advertisements
Advertisements

Question

Making use only of substances chosen from those given below:
Dilute sulphuric acid
Sodium carbonate
Zinc
Sodium sulphite
Lead
Salcium carbonate

Give the equation for the reaction by which you could obtain:
(i) Hydrogen
(ii) Sulphur dioxide
(iii) Carbon dioxide
(iv) Zinc Carbonate (two steps required).

Short Note

Solution

(i) Zinc reacts with dilute sulphuric acid to evolve hydrogen.

\[\ce{Zn + H2SO4 → ZnSO4 + H2 ^}\]

(ii) Sodium sulphite reacts with dilute sulphuric acid to give sulphur dioxide.

\[\ce{Na2SO3 + H2SO4 → Na2SO4 + H2O + SO2 ^}\]

(iii) Sodium carbonate reacts with dilute sulphuric acid to give carbon dioxide.

\[\ce{Na2CO3 + H2SO4 → Na2SO4  + H2O + CO2 ^}\]

(iv) Zinc reacts with dilute sulphuric acid to form zinc sulphate, which in reaction with sodium carbonate forms zinc carbonate.

\[\ce{ Zn + H2SO4 → ZnSO4 + H2 ^}\]

\[\ce{ZnSO4 + Na2CO3 → ZnCO3 + Na2SO4}\]

shaalaa.com
Sulphuric Acid
  Is there an error in this question or solution?
Chapter 10: Study of Sulphur Compound: Sulphuric Acid - Exercise 6 [Page 254]

APPEARS IN

Frank Chemistry - Part 2 [English] Class 10 ICSE
Chapter 10 Study of Sulphur Compound: Sulphuric Acid
Exercise 6 | Q 6 | Page 254
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×