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Match the correct atomic radius with the element. Element Atomic radius (pm) Be 74 C 88 O 111 B 77 N 66 - Chemistry

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Question

Match the correct atomic radius with the element.

Element Atomic radius (pm)
\[\ce{Be}\] 74
\[\ce{C}\] 88
\[\ce{O}\] 111
\[\ce{B}\] 77
\[\ce{N}\] 66
Match the Columns

Solution

Element Atomic radius (pm)
\[\ce{Be}\] 111
\[\ce{C}\] 77
\[\ce{O}\] 66
\[\ce{B}\] 88
\[\ce{N}\] 74

Explanation:

All the given elements are of same period and along period, atomic radii decrease because effective nuclear charge increases.

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Chapter 3: Classification of Elements and Periodicity in Properties - Multiple Choice Questions (Type - I) [Page 34]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 3 Classification of Elements and Periodicity in Properties
Multiple Choice Questions (Type - I) | Q 43 | Page 34
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