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Question
Match the following:
Column I | Column II |
(i) `a/b ÷ a/b` | (a) `(-a)/b` |
(ii) `a/b ÷ c/d` | (b) –1 |
(iii) `a/b ÷ (-1)` | (c) 1 |
(iv) `a/b ÷ (-a)/b` | (d) `(bc)/(ad)` |
(v) `b/a ÷ (d/c)` | (e) `(ad)/(bc)` |
Solution
Column I | Column II |
(i) `a/b ÷ a/b` | (c) 1 |
(ii) `a/b ÷ c/d` | (e) `(ad)/(bc)` |
(iii) `a/b ÷ (-1)` | (a) `(-a)/b` |
(iv) `a/b ÷ (-a)/b` | (b) –1 |
(v) `b/a ÷ (d/c)` | (d) `(bc)/(ad)` |
Explanation:
(i) Given, `a/b ÷ a/b = a/b xx b/a` ......`[∵ "Reciprocal of " a/b = b/a]`
= 1
(ii) Given, `a/b ÷ c/d = a/b xx d/c` ......`[∵ "Reciprocal of " c/d = d/c]`
= `(ad)/(bc)`
(iii) Given, `a/b ÷ (-1) = a/b xx (-1)` ......[∵ Reciprocal of –1 = –1]
= `(-a)/(b)`
(iv) Given, `a/b ÷ (-a)/b = a/b xx ((-b)/a)` ......`[∵ "Reciprocal of" (-a)/b = (-b)/a]`
= –1
(v) Given, `b/a + (d/c) = b/a xx c/d` ......`[∵ "Reciprocal of " d/c = c/d]`
= `(bc)/(ad)`
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