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Match the following: (i) 425 × 136 = 425 × (6 + 30 +100) (a) Commutativity under multiplication. (ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition. (iii) 80 + 2005 + 20 = 80 + 20 + 2005 - Mathematics

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Question

Match the following:

(i) 425 × 136 = 425 × (6 + 30 +100) (a) Commutativity under multiplication.
(ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition.
Match the Columns

Solution

(i) 425 × 136 = 425 × (6 + 30 +100) (c) Distributivity of multiplication over addition.
(ii) 2 × 49 × 50 = 2 × 50 × 49 (a) Commutativity under multiplication.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (b) Commutativity under addition.
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Chapter 2: Whole Numbers - Exercise 2.2 [Page 41]

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NCERT Mathematics [English] Class 6
Chapter 2 Whole Numbers
Exercise 2.2 | Q 7. | Page 41

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