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Minimize: Z = 2x + Y , Subject To: X + Y < 5 - Mathematics and Statistics

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Question

Minimize: Z = 2x + y 

Subject to: x + y ≤ 5 

x + 2y ≤  8 

4x + 3y ≥ 12 

x ≥  o,  y ≥ o 

Solve graphically.

Graph
Sum

Solution

Constraints

Corresponding equations

Points on
X-axis Y-axis
1. x + y ≤ 5 x + y = 5 A (5 , 0) B (0 , 5)
2. x + 2y ≤ 8 x + 2y = 8 C (8 , 0) D (0 ,4)
3. 4x + 3y ≥ 12 4x + 3y = 12 E (3 , 0) F (0 , 4)

 

From the graph, the shaded region seg EAGDF is the feasible region.

The objective function Z = 2x + y will be minimum at the vertices of the feasible region EAGDF.

G is the point of ~ntersection of the lines

x + y = 5 and x + 2y = 8

By solving this simultaneous equation, we will get

x = 2 and y = 3

∴ G(2, 3) .

Now calculate Z = 2x + y at each vertex of the feasible region EAGDF at E, Z(3,0)  = 2  × 3 + 0 = 6 

At A , Z(5,0)  = 2  × 5 + 0 = 10 

At G , Z(2,3)  = 2  × 2 + 3 = 7

At D , Z(0,4)  = 2  × 0 + 4 = 4

From the above calculation Z is minimum at D(0,4). 

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