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Question
Mr. Mehta sold his two luxury cars at Rs. 39,10,000 each. On one he gains 15% but on the other, he loses 15%. How much does he gain or lose in the whole transaction?
Solution
Let x, y be the C.P. of two cars.
S.P. of both the cars = 39,10,000 .....…[Given]
∴ One car is sold at a 15% loss
∴ S.P. of the first car = `"x" - 15/100 "x"`
∴ `85/100 "x"` = 39,10,000
∴ x = `(39,10,000 xx 100)/85`
= `(2,30,000 xx100)/5`
= 46,000 × 100
= 46,00,000
Other car is sold at 15% gain
∴ S.P. of second car = `"y" + 15/100 "y"`
∴ `"y" + 15/100 "y" = 39,10,000`
∴ `115/100 "y" = 39,10,000`
∴ y = `(39,10,000 xx 100)/115`
= `(7,82,000 xx 100)/23`
= 34,000 × 100
= 34,00,000
x + y = Total C.P. of two cars
= 46,00,000 + 34,00,000
= 80,00,000
Total S.P. = 39,10,000 + 39,10,000
= 78,20,000
∴ S.P. < C.P.
∴ There is a loss of ₹ (80,00,000 – 78,20,000)
∴ = ₹ 1,80,000
∴ Loss% = `(1,80,000)/(80,00,000) xx 100`
= `18/8`
= `9/4`
= 2.25
∴ Mr. Mehta bears a 2.25% loss in the whole transaction.
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