Advertisements
Advertisements
Question
Multiply: `-2/3"a"^7"b"^2` and `-9/4"a""b"^5`
Solution
`(-2/3"a"^7"b"^2)(-9/4"ab"^5)`
= `(-2/3xx(-9)/4)("a"^7xx"a")("b"^2xx"b"^5)`
= `3/2"a"^8"b"^7`
APPEARS IN
RELATED QUESTIONS
Find the product of the following pair of monomial.
4, 7p
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths, respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Obtain the product of 2, 4y, 8y2, 16y3
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( \frac{1}{8} x^2 y^4 \right) \times \left( \frac{1}{4} x^4 y^2 \right) \times \left( xy \right) \times 5\]
Multiply: x + 4 by x − 5
Multiply: 2m2 − 3m − 1 and 4m2 − m − 1
Multiply: a2, ab and b2
Product of the following monomials 4p, – 7q3, –7pq is ______.
Multiply the following:
3x2y2z2, 17xyz
Multiply the following:
(p + 6), (q – 7)
