Advertisements
Advertisements
Question
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
Sum
Solution
`(2"a"^3-3"a"^2"b")(-1/2"ab"^2)`
= `-1/2"ab"^2 (2"a"^3-3"a"^2"b")`
= `2"a"^3xx-1/2"ab"^2-3"a"^2"b"xx-1/2"ab"^2`
= `-"a"^4"b"^2+3/2"a"^3"b"^3`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Find the product of the following pair of monomial.
− 4p, 7p
Find the product of the following pair of monomial.
4p3, − 3p
Obtain the product of 2, 4y, 8y2, 16y3
Multiply: a2, ab and b2
Multiply: abx, −3a2x and 7b2x3
A total of 90 currency notes, consisting only of ₹ 5 and ₹ 10 denominations, amount to ₹ 500. Find the number of notes in each denomination.
Multiply the following:
–7pq2r3, –13p3q2r
Multiply the following:
3x2y2z2, 17xyz
Multiply the following:
–5a2bc, 11ab, 13abc2
Multiply the following:
7pqr, (p – q + r)