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Multiply the following: –5a2bc, 11ab, 13abc2 - Mathematics

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Question

Multiply the following: 

–5a2bc, 11ab, 13abc2

Sum

Solution

We have,

–5a2bc, 11ab and 13abc2

∴ –5a2bc × 11ab × 13abc2 = (–5 × 11 × 13)a2bc × ab × abc2

= –715a4b3c3

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 230]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 83. (iv) | Page 230

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