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Question
Multiply and then verify :
−3x2y2 and (x – 2y) for x = 1 and y = 2.
Solution
(−3x2y2) × (x – 2y)
= (−3x2y2) × (x) − (−3x2y2)(2y)
= −3x2y2 + 6x2y3
= 6x2y3 − 3x3y2
For x = 1 and y = 2
(−3x2y2) × (x – 2y)
= (−3 × 12 × 22) × (1 − 2 × 2)
= (6 × 1 × 8) − (3 × 1 × 4)
= 48 − 12
= 36
∴ For x = 1 and y = 2, it is verified that,
(−3x2y2) × (x – 2y)
= 6x2y3 − 3x3y2
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