Advertisements
Advertisements
Question
Nitric acid is an oxidising agent and reacts with \[\ce{PbO}\] but it does not react with \[\ce{PbO2}\]. Explain why?
Solution
\[\ce{PbO}\] is a basic oxide and simple acid base reaction takes place between \[\ce{PbO}\] and \[\ce{HNO3}\]. On the other hand in \[\ce{PbO2}\] lead is in + 4 oxidation state and cannot be oxidised further. Therefore no reaction takes place. Thus, \[\ce{PbO2}\] is passive, only \[\ce{PbO}\] reacts with \[\ce{HNO3}\].
\[\ce{2PbO + 4HNO3 -> 2Pb (NO3)2 + 2H2O}\] (Acid base reaction)
APPEARS IN
RELATED QUESTIONS
What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
KI3
Consider the elements: Cs, Ne, I and F
Identify the element that exhibits both positive and negative oxidation states.
\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:
\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]
\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]
Why do these compounds differ in their reactivity?
Calculate the oxidation number of phosphorus in the following species.
\[\ce{PO^{3-}4}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2S4O6}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO4}\]
The oxidation number of P in Mg2P207 is ____________.
The oxidation number and covalency of sulphur in sulphur molecules (Sg) are:
Oxidation number of potassium in K2O, K2O2 and KO2, respectively, is ______.
Oxidation state of sulphur in anions `"SO"_3^(2-)`, `"S"_2"O"_4^(2-)` and `"S"_2"O"_6^(2-)` increases in the orders: