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Question
One of the angles of a triangle is 110°, the two other angles are equal. Find their value.
Solution
Let in Δ ABC,
∠A = 110° and ∠B = ∠C
But ∠A + ∠B + ∠C = 180°
⇒ 110° + ∠B + ∠B = 180°
⇒ 2 ∠B = 180° - 110°
⇒ 2 ∠B = 70°
⇒ ∠B = `70^circ/2 = 35^circ`
∴ ∠C = ∠B = 35°
Hence each of two equal angles is 35°
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