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Question
\[\ce{pH}\] of a solution of a strong acid is 5.0. What will be the \[\ce{pH}\] of the solution obtained after diluting the given solution a 100 times?
Solution
\[\ce{pH}\] = 5 i.e., \[\ce{[H+]}\] = 10–5 mol L–1
On dilution by 100 times \[\ce{[H+]}\] = 10–7 mol L–1 For a very dilute solution,
Total \[\ce{[H+]}\] = [\[\ce{H3O+}\] ions from acid] + [\[\ce{H2O+}\] ions from water]
= 10–7 + 10–7
\[\ce{pH}\] = – log\[\ce{[H+]}\] = – log (2 × 10–7) = 7 – log 2
= 7 – 0.3010 = 6.6990
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