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Prove the theorem of perpendicular axes about the moment of inertia. -

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Question

Prove the theorem of perpendicular axes about the moment of inertia.

Numerical

Solution

Theorem of perpendicular axes

Proof: Let Oz be an axis perpendicular to the lamina's plane, and let Ox and Oy be two perpendicular axes in the lamina's plane. At point P(x, y), consider an infinitesimal mass element (dm) of the lamina. MI centred on the z-axis in the lamina

Iz = ∫ OP2 dm`

The element is perpendicular to the x - and y - axes, respectively, at a distance of y and x. Because of this, the lamina's moments of inertia about the x - and y -axes are, respectively,

Ix = ∫ y2 dm and Iy = ∫ x2 dm 

Since OP2 = y2 + x2,

Iz = ∫ OP2 dm

= ∫ (y2 + x2) dm

= ∫ y2 dm + ∫ x2 dm

= ∴ Iz = Ix + Iy

This proves the theorem of perpendicular axes.

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