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Question
Q 7
Sum
Solution
y = x + x2 + x3 +.............∞, where |x| < 1
⇒ y = x(1 + x + x2 + ............∞)
⇒ y = x`[1/(1-x)]`
⇒ y (1 - x) = x
⇒ y - xy = x
⇒ y = x + xy
⇒ y = x(1 + y)
⇒ `y/(1+y)=x`
⇒ `x=y/(1+y)`
shaalaa.com
Simple Applications - Geometric Progression
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