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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 6

Rahim and Peter go for a morning walk, Rahim walks around a square path of side 50 m and Peter walks around a rectangular path with length 40 m and breadth 30 m. If both of them walk 2 rounds - Mathematics

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Question

Rahim and Peter go for a morning walk, Rahim walks around a square path of side 50 m and Peter walks around a rectangular path with length 40 m and breadth 30 m. If both of them walk 2 rounds each, who covers more distance and by how much?

Sum

Solution

Perimeter of the square = (4 × side) units

Side of the square = 50 m

∴ Perimeter = 4 × 50 m = 200 m

Rahim walked twice around the park

∴ Total distance walked by Rahim = 2 × 200 m

Total distance covered by Rahim = 400 m

Perimeter of a rectangle = 2(length + breadth) unit

Length = 40 m

Breadth = 30 m

∴ Perimeter = 2 × (40 + 30) m

= (2 × 70) m

= 140 m

Peter walked around twice

∴ Distance covered by Peter = 2 × 140 m

= 280 m

∴ Distance covered by Peter = 280 m

400 m > 280 m

Difference = 480 – 280

= 120 m

∴ Rahim covers 120 m more than Peter

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Chapter 3: Perimeter and Area - Exercise 3.2 [Page 53]

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Samacheer Kalvi Mathematics - Term 3 [English] Class 6 TN Board
Chapter 3 Perimeter and Area
Exercise 3.2 | Q 3 | Page 53
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