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Question
Ramesh bought two boxes for Rs 1300. He sold one box at a profit of 20% and the other box at a loss of 12%. If the selling price of both boxes is the same, find the cost price of each box.
Solution
\[\text { Let the cost price of the first box be Rs . x } . \]
\[\text { Therefore, the cost of the second box will be Rs } . (1300 - x)\]
\[\text { Profit on the first box = 20 %} \]
\[\text { Loss on the second box = 12 % } \]
\[\text { SP of the first box = C }P\left( \frac{\text { gain %} + 100}{100} \right)\]
\[SP = x\left( \frac{120}{100} \right)\]
\[\text { SP of the first box = Rs } . \frac{120x}{100} = Rs . \frac{6x}{5}\]
\[\text { SP of the second box = CP }\left( \frac{100 -\text { loss %}}{100} \right)\]
\[\text { S . P of the second box }= \frac{88\left( 1300 - x \right)}{100} = Rs . \left( \frac{28600 - 22x}{25} \right)\]
\[\text { Since S . P of both the box are equal }, \]
\[\frac{6x}{5} = \left( \frac{28600 - 22x}{25} \right)\]
\[150x = 143000 - 110x\]
\[260x = 143000\]
\[x = \frac{143000}{260}\]
\[x = 550\]
\[\text { Therefore, the cost price of the first box is Rs . 550 }. \]
\[\text { The cost price of the second box will be Rs } . (1300 - 550) = Rs . 750\]
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Fill up the appropriate boxes in the following table.
| SI. No | C.P. in ₹ |
M.P. in ₹ |
S.P. in ₹ |
Discount in ₹ |
Profit in ₹ |
Loss in ₹ |
| (i) | 110 | 130 | Nil | |||
| (ii) | 110 | 130 | 10 | |||
| (iii) | 110 | 130 | 30 | |||
| (iv) | 110 | 120 | Nil | 10 | ||
| (v) | 120 | 10 | 20 | Nil |
A TV set was bought for Rs 26,250 including 5% VAT. The original price of the TV set is ______.
On selling an article for ₹ 329, a dealer lost 6%. The cost price of the article is ______.
A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹ 4000, then find the CP of the scooter.
