Question

Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car ( with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with
base dimensions 4 m × 3m?

Answer 1

Given that

Shelter length = 4m
Breadth = 3m
Height = 2.5m
The tarpaulin will be required for four sides of the shelter

Area of tarpaulin in required${\displaystyle =2(lb+bh+hl)}$

${\displaystyle =[2\left(4\right)\times 2.5+(3\times 2.5)+4\times 3]m^2}$

${\displaystyle =[2(10+7.5)+12]m^2}$

${\displaystyle 47m^2=47m^2}$