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Maharashtra State BoardSSC (English Medium) 9th Standard

Ray PQ and ray PR are perpendicular to each other. Points B and A are in the interior and exterior of ∠QPR respectively. Ray PB and ray PA are perpendicular to each other. - Geometry

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Question

Ray PQ and ray PR are perpendicular to each other. Points B and A are in the interior and exterior of ∠QPR respectively. Ray PB and ray PA are perpendicular to each other. Draw a figure showing all these rays and write -

  1. A pair of complementary angles  
  2. A pair of supplementary angles. 
  3. A pair of congruent angles.
Sum

Solution

Since ray PQ ⊥ ray PR, then m∠QPR = 90 and ray PA ⊥ ray PB, then m∠APB = 90.

(i) Two angles, sum of whose measures is 90, are called complementary angles.

Here, m∠QPR = 90

⇒ m∠BPQ + m∠BPR = 90

∴ ∠BPQ and ∠BPR are complementary angles.

(ii) Two angles, sum of whose measures is 180, are called supplementary angles.

⇒ m∠APB + m∠QPR 

= 90 + 90 

= 180

∴ ∠APB and ∠QPR are supplementary angles.

(iii) Angles with the same measures are called congruent angles.

Here, m∠QPR = m∠APB = 90

∴ ∠APB and ∠QPR are congruent angles.

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Use of properties of parallel lines
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Chapter 2: Parallel Lines - Problem Set 2 [Page 22]

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Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 2 Parallel Lines
Problem Set 2 | Q 2. | Page 22
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