Advertisements
Advertisements
Question
Shobo’s mother’s present age is six times Shobo’s present age. Shobo’s age five years from now will be one third of this mother’s present age. What are their present ages?
Solution
Let Shobo’s age be x years. Therefore, his mother’s age will be 6x years.
According to the given question,
After 5 years Shobo's age = `"Shobo's mother's present age"/3``
`x + 5 = (6x)/3`
x + 5 = 2x
Transposing x to R.H.S, we obtain
5 = 2x − x
5 = x
6x = 6 × 5 = 30
Therefore, the present ages of Shobo and Shobo’s mother will be 5 years and 30 years respectively.
APPEARS IN
RELATED QUESTIONS
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?
One of the two digits of a two digit number is three times the other digit. If you interchange the digit of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?
Half of a herd of deer are grazing in the field and three fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.
A grandfather is ten times older than his granddaughter. He is also 54 years older than her. Find their present ages
Arjun is twice as old as Shriya. Five years ago his age was three times Shriya’s age. Find their present ages.
A and B are together 90 years old. Five years ago A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years respectively.
Sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number.
After 12 years, Kanwar shall be 3 times as old as he was 4 years ago. Find his present age.
In a two-digit number, digit in units place is twice the digit in tens place. If 27 is added to it, digits are reversed. Find the number.
