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Show That: 3 √ 64 × 729 = 3 √ 64 × 3 √ 729 - Mathematics

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Question

Show that: \[\sqrt[3]{64 \times 729} = \sqrt[3]{64} \times \sqrt[3]{729}\]

Sum

Solution

LHS =  \[\sqrt[3]{64 \times 729} = \sqrt[3]{4 \times 4 \times 4 \times 9 \times 9 \times 9} = \sqrt[3]{\left\{ 4 \times 4 \times 4 \right\} \times \left\{ 9 \times 9 \times 9 \right\}} = 4 \times 9 = 36\] 

RHS = \[\sqrt[3]{64} \times \sqrt[3]{729} = \sqrt[3]{4 \times 4 \times 4} \times \sqrt[3]{9 \times 9 \times 9} = 4 \times 9 = 36\]

Because LHS is equal to RHS, the equation is true.

 
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Chapter 4: Cubes and Cube Roots - Exercise 4.4 [Page 30]

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RD Sharma Mathematics [English] Class 8
Chapter 4 Cubes and Cube Roots
Exercise 4.4 | Q 2.2 | Page 30

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