Advertisements
Advertisements
Question
Find the cube-root of 700 × 2 × 49 × 5.
Solution
700 × 2 × 49 × 5
= 2 × 2 × 5 × 5 × 7 × 2 × 7 × 7 × 5
= (2 × 2 × 2) × (5 × 5 × 5) × (7 × 7 × 7)
= 2 × 5 × 7
= 70
APPEARS IN
RELATED QUESTIONS
Find the smallest number by which the following number must be multiplied to obtain a perfect cube.
243
Find the smallest number by which of the following number must be divided to obtain a perfect cube.
128
Find the smallest number by which the following number must be divided to obtain a perfect cube.
704
Write the cubes of 5 natural numbers which are of the form 3n + 1 (e.g. 4, 7, 10, ...) and verify the following:
'The cube of a natural number of the form 3n + 1 is a natural number of the same form i.e. when divided by 3 it leaves the remainder 1'.
What is the smallest number by which the following number must be multiplied, so that the products is perfect cube?
107811
What happens to the cube of a number if the number is multiplied by 5?
Which of the following number is cube of negative integer - 64 .
Show that the following integer is cube of negative integer. Also, find the integer whose cube is the given integer −5832 .
Making use of the cube root table, find the cube root
7000
Find if the following number is a perfect cube?
24000
Find the least number by which 1323 must be multiplied so that the product is a perfect cube.
Find the cube-root of 1728.
Find the cube-root of `125/216`
Find the cube-root of 64 x 27.
Find the cube-root of 729 x 8000
Find the cube-root of -216
Find the cube-root of 9.261
Find the smallest number by which 10985 should be divided so that the quotient is a perfect cube
Find the cube root 24 × 36 × 80 × 25
If a2 ends in 5, then a3 ends in 25.
