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Show that the Solution Set of the Following System of Linear Inequalities is an Unbounded Region: 2 X + Y ≥ 8 , X + 2 Y ≥ 10 , X ≥ 0 , Y ≥ 0 - Mathematics

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Question

Show that the solution set of the following system of linear inequalities is an unbounded region:  

\[2x + y \geq 8, x + 2y \geq 10, x \geq 0, y \geq 0\] 

Solution

\[\text{ We have }, \]
\[2x + y \geq 8 . . . . . \left( i \right)\]
\[x + 2y \geq 10 . . . . . \left( ii \right)\]
\[x \geq 0 . . . . . \left( iii \right)\]
\[y \geq 0 . . . . . \left( iv \right)\]

As, the solutions of the equation 2x + y = 8 are:

x 0 4 2
y 8 0 4

As, the solutions of the equation x + 2y = 10 are: 

x 0 10 2
y 5 0 4

Now, the graph represented by the inequalities (i), (ii), (iii) and (iv) is as follows:

Since, the common shaded region is the solution set of the given set of inequalities.

So, the solution set of the given linear inequalities is an unbounded region.

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Chapter 15: Linear Inequations - Exercise 15.6 [Page 31]

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RD Sharma Mathematics [English] Class 11
Chapter 15 Linear Inequations
Exercise 15.6 | Q 8 | Page 31

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