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Show that the System Equations 2x - 3y = 5, 6x - 9y = 15 Has an Infinite Number of Solutions - Mathematics

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Question

Show that the system equations
2x - 3y = 5,
6x - 9y = 15

has an infinite number of solutions

Solution

The given system of equations:
2x - 3y = 5
⇒ 2x - 3y – 5 = 0            ….(i)
6x - 9y = 15
⇒6x - 9y - 15 = 0              …(ii)
These equations are of the following forms:
`a_1x+b_1y+c_1 = 0, a_2x+b_2y+c_2 = 0`
Here, `a_1 = 2, b_1= -3, c_1= -5 and a_2 = 6, b_2= -9, c_2= -15`
`∴ (a_1)/(a_2) = 2/6 = 1/3 ,(b_1)/(b_2) = (−3)/(−9) = 1/3 and (c_1)/(c_2 )= (−5)/(−15) = 1/3`
Thus, `(a_1)/(a_2) = (b_1)/(b_2) = (c_1)/(c_2)`
Hence, the given system of equations has an infinite number of solutions.

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Chapter 3: Linear Equations in two variables - Exercises 4

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RS Aggarwal Mathematics [English] Class 10
Chapter 3 Linear Equations in two variables
Exercises 4 | Q 10

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