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Since Displacement Current is Equal to the Charging Current, the Value of Displacement Current is Also 0.25 A. - Physics

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Question

The charging current for a capacitor is 0.25 A.  What is the displacement current across its plates?

Solution

Since displacement current is equal to the charging current, the value of displacement current is also 0.25 A.
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2015-2016 (March) Foreign Set 2

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RELATED QUESTIONS

A parallel plate capacitor (Figure) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s−1.

  1. What is the rms value of the conduction current?
  2. Is the conduction current equal to the displacement current?
  3. Determine the amplitude of B at a point 3.0 cm from the axis between the plates.


When an ideal capacitor is charged by a dc battery, no current flows. However, when an ac source is used, the current flows continuously. How does one explain this, based on the concept of displacement current?


If the total energy of a particle executing SHM is E, then the potential energy V and the kinetic energy K of the particle in terms of E when its displacement is half of its amplitude will be ______.


A cylinder of radius R, length Land density p floats upright in a fluid of density p0. The cylinder is given a gentle downward push as a result of which there is a vertical displacement of size x; it is then released; the time period of resulting (undampe (D) oscillations is ______.


Which of the following is the unit of displacement current?


According to Maxwell's hypothesis, a changing electric field gives rise to ______.


A capacitor of capacitance ‘C’, is connected across an ac source of voltage V, given by

V = V0sinωt 

The displacement current between the plates of the capacitor would then be given by:


An electromagnetic wave travelling along z-axis is given as: E = E0 cos (kz – ωt.). Choose the correct options from the following;

  1. The associated magnetic field is given as `B = 1/c hatk xx E = 1/ω (hatk xx E)`.
  2. The electromagnetic field can be written in terms of the associated magnetic field as `E = c(B xx hatk)`.
  3. `hatk.E = 0, hatk.B` = 0.
  4. `hatk xx E = 0, hatk xx B` = 0.

A long straight cable of length `l` is placed symmetrically along z-axis and has radius a(<< l). The cable consists of a thin wire and a co-axial conducting tube. An alternating current I(t) = I0 sin (2πνt) flows down the central thin wire and returns along the co-axial conducting tube. The induced electric field at a distance s from the wire inside the cable is E(s,t) = µ0I0ν cos (2πνt) In `(s/a)hatk`.

  1. Calculate the displacement current density inside the cable.
  2. Integrate the displacement current density across the cross-section of the cable to find the total displacement current Id.
  3. Compare the conduction current I0 with the displacement current `I_0^d`.

Draw a neat labelled diagram of displacement current in the space between the plates of the capacitor.


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