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Question
Solid ammonium dichromate decomposes as:
\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]
If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of (NH4)2Cr2O7.
Solution
Molecular mass of ammonium dichromate = 2(14 + 4) + 104 + 112
= 252 g
Number of moles = `"Weight"/"Molecular weight"`
= `63/252`
= 0.25 moles
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